A gas occupies 50.0 ml at standard temperature and pressure. if the volume of gas increases to 120ml, what is the new pressure

Ok so, P1V1 = P2V2 this is ... (1atm) (50 ml) = (x atm) (120 ml)

Algebraically the answer should be 0.416 atm. which does make sense b/c in volume is increasing, vapor pressure is lowering.