How many grams of calcium nitrate are needed to make 3.30 L of a 0.10 M solution?

54.15 g

First you start out with the equation n=cv (n = moles, c=molarity, v = volume)

You’re going to multiply 0.10M by 3.30L to get an answer of 0.33 moles of Ca (NO3) 2

From there you’re gonna convert the moles to grams to get your answer, first you have to find the molar mass of Ca (NO3) 2

This can be done by finding adding the molar mass of each individual substance

The answer you should get for the molar mass is 164.1 g

From there just multiply the number of moles you calculated (0.33 mol) by the molar mass (164.1 g) and your answer is going to be 54.15 g Ca (NO3) 2