When a gas is pumped into a small rigid container the pressure inside the container increases as more particles are added. If the number of particles is doubled then the pressure will double. What would happen if the number of particles were decreased by half?

Since the container of the gas is rigid, the volume of the gas will remain constant. Therefore, when the number of particles were decreased in half then the pressure will also be half of the original given they both are subjected to the same temperature.

PV = nRT

V, T and R are constants so they can be lumped together to a constant k.

P/n = k

P1/n1 = P2/n2

since n2 = n1/2

P1/n1 = P2 / n1/2

P2 = P1/2