What is the pH of a 9.50*10-2 M ammonia solution?

NH₃ + H₂O ⇄ NH₄⁺ + OH⁻

c=9,50*10⁻² mol/L

Ammonia solution is a weak electrolyte.

The dissociation constant of ammonium hydroxide is:

K=1.78*10⁻⁵

[OH⁻]=√ (Kc)

pH=14-pOH=14+lg[OH]⁻

pH=14+lg (√ (Kc))

pH=14+lg (√ (1.78*10⁻⁵*9.50*10⁻²)) = 8.23

pH=8.23