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14 August, 01:36

What mass of anhydrous solute is needed to prepare 2.25L of 0.141 M K2SO4 (aq) ? answer in units of g

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  1. 14 August, 03:52
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    M = mol/L

    So mol = 2.25L (.141M) =.317mol

    Molar mass of K2SO4 = 174.259g

    Stoich:

    .317mol (174.259g) = 46.7g

    Ans: 46.7g
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