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29 March, 17:47

2.40 g of NH4Cl is added to 19.4 g of water. Calculate the molality of the solution.

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  1. 29 March, 19:03
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    Molality is the moles of solute per kg of solvent.

    Moles of NH₄Cl = 2.4 / (14 + 4 x 1 + 35.5)

    = 0.0448 mole

    Molality = 0.0448 / (19.4 / 1000)

    = 2.31 m
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