Write complete ionic equation to show the reaction of aqueous lead (II) nitrate with aqueous potassium sulfate to form solid lead (II) sulfate and aqueous potassium nitrate.

The correct answer to this question is this one:

Pb (N O3) 2 (aq) + K2 S O4 (aq) →PbS O4 (s) + 2KN O3 (aq)

Everything except the lead sulfate is soluble, so they all dissociate.

P b 2 + + 2N O-3 + 2 K + + S O 2 - 4 →PbS O4 (s) + 2 K + + 2N O-3

Cancel out stuff that appears on both sides, and your net ionic equation is

P b 2 + (aq) + S O 2 - 4 (aq) →PbS O4 (s)