Part b what is the maximum mass, in grams, of nh3 that can be produced by the reaction of 1.0 g of n2 and 1.0 g of h2 using the reaction below? n2+h2? nh3 (not balanced)

3H₂ + N₂ = 2NH₃

n (H₂) = m (H₂) / M (H₂)

n (H₂) = 1.0/2.0=0.5 mol

n (N₂) = m (N₂) / M (N₂)

n (N₂) = 1.0/28.0=0.0357 mol

H₂:N₂ = 3:1

0.5:0.0357 = 3:0.2142 nitrogen is a limiting reagent

n (NH₃) = 2n (N₂)

m (NH₃) = 2n (N₂) M (NH₃)

m (NH₃) = 2*0.0357*17.0=1.214 g