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3 May, 05:59

What mass of phosphoric acid (h3po4, 98.0 g/mol) is produced from the reaction of 10.0 g of p4o10 (284 g/mol) with excess water?

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  1. 3 May, 09:11
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    When the balanced reaction equation is:

    P4O10 + 6H2O→ 4 H3PO4

    when we have the mass of P4O10 = 10 g and the molar mass of P4O10=284 g/mol & we have the molar mass of H3PO4 = 98 g/mol so we can get the mass of H3PO4 by substitution by:

    mass of H3PO4 = (mass of P4O10) / (molar mass of P4O10) * 4 (mol of H3PO4) * molar mass of H3PO4

    ∴mass of H3PO4 = (10 / 284) * 4 * 98 = 13.8 g
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