4.5 moles of sodium sulfate contain how many atoms of sulfur

Chemical Formula of Sodium Sulfate is Na₂SO₄.

As we know, 1 mole of any substance contains 6.022 * 10²³ particles. So, 1 mole of Na₂SO₄ also contains 6.022 * 10²³ formula units of Na₂SO₄.

Also,

1 mole of Na₂SO₄ contains = 6.022 * 10²³ Atoms of S

So,

4.5 moles of Na₂SO₄ will contain = X atoms of S

Solving for X,

X = (4.5 moles * 6.022 * 10²³ Atoms) : 1 mole

X = 2.70 * 10²⁴ Atoms of S

Result:

4.5 Moles of Na₂SO₄ contains 2.70 * 10²⁴ Atoms of Sulfur.