A sample of neon gas occupies 0.220L at 0.860atm. What will be it's new volume at 1.52 atm, assuming the temperature remains constant.

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Chemistry

Dottie

4 April, 20:51

A sample of neon gas occupies 0.220L at 0.860atm. What will be it's new volume at 1.52 atm, assuming the temperature remains constant.

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Bryce Smith · Answer 1

The new volume at 1.52 atm is calculated by use of Bolyes law formula

that is P1V1=P2V2

V1 = 0.220 L

P1 = 0.860 atm

P2 = 1.52 atm

V2=?

V2 is therefore = P1V1/P2

= (0.220 L x 0.860 atm) / 1.52 atm = 0.1245 Liters