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26 January, 14:45

An aqueous solution has an h3o + concentration of 4.4*10-2 m. calculate [oh-] for this solution.

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  1. 26 January, 15:45
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    First calculate Ph

    Ph = - log (H3O+)

    Ph=-log (4.4 x10^-2) = 1.4

    Ph + Poh=14

    Poh is therefore = 14 - 1.4=12.6

    Oh - concentration is calculated as follows

    1 x10^ - POh

    that is 1 x10^-12.6 which is = 2.5 x10^-13
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