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28 August, 20:02

A reaction has a forward rate constant of 2.3 * 106 s-1 and an equilibrium constant of 4.0 * 108. what is the rate constant for the reverse reaction?

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  1. 28 August, 23:05
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    Answer is: 5,75·10⁻¹.

    Kf = 2,3·10⁶ 1/s.

    K = 4,0·10⁸ 1/s.

    Kr = ?

    Kf - forward rate constant.

    K - equilibrium constant.

    Kr - reverse rate constant.

    Since both Kf and Kr are constants at a given temperature, their ratio is also a constant that is equal to the equilibrium constant K.

    K = Kf/Kr.

    Kr = Kf/K = 2,3·10⁶ 1/s : 4,0·10⁸ 1/s = 5,75·10⁻¹.
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