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22 September, 03:09

What is the volume of 3.40 mol of gas at 33.3C and 22.2atm of pressure

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  1. 22 September, 05:05
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    The volume of 3.40 mol of gas at 33.3 C and 22.2 atm of pressure is 3.85 liter of gas. This problem can be solved by using the PV=nRT or V = nRT/V equation which is the relation between the molar volume, the temperature, and the pressure of gas. In this formula, P is the pressure, R is the universal gas constant (0.0821 atm L/mol K), n is the molecule amount, V is the molecular volume, and T is the temperature. The temperature used in this formula must be in Kelvin, therefore we have to convert the Celcius temperature into Kelvin temperature (33.3 C = 306.45 K).

    The calculation for the problem above: 3.4*0.0821*306.45/22.2 = 3.85 liter of gas.
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