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28 December, 15:23

If the pOH of vinegar is 9.45, what is its [OH - ]?

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  1. 28 December, 16:26
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    [OH⁻] = 3.54 * 10⁻¹⁰ M

    Solution:

    pOH is related to [OH⁻] as,

    pOH = - log [OH⁻]

    Putting value of pOH,

    9.45 = - log [OH⁻]

    Solving for [OH⁻],

    [OH⁻] = 10⁻⁹·⁴⁵ ∴ 10 = Antilog

    [OH⁻] = 3.54 * 10⁻¹⁰ M
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