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10 July, 20:29

The half-life of phosphorus-32 is 14.30 days. how many milligrams of a 20.00 mg sample of phosphorus-32 will remain after 85.80 days?

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  1. 10 July, 20:57
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    The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.

    A (t) = A (o) (1/2) ^ (t/d)

    where t is the certain period of time. Substituting the known values,

    A (t) = (20 mg) (1/2) ^ (85.80/14.30)

    Solving,

    A (t) = 0.3125 mg

    Hence, the answer is 0.3125 mg.
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