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12 September, 10:15

If 18.6 ml of 0.800 m hcl solution are needed to neutralize 5.00 ml of a household ammonia solution, what is the molar concentration of the ammonia? nh3 (aq) + hcl (aq) →nh4cl (aq)

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  1. 12 September, 10:21
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    Molarity of HCl = number of moles / volume

    Number of moles = Molarity of Hcl * volume

    No of moles = 0.8 * 18.6 * 10^ (-3) = 14.88 * 10^ (-3)

    From the equation one mole of HCl reacts with one mole of ammonia

    Hence number of moles of ammonia = 14.88 * 10^ (-3)

    From question volume of ammonia = 5 * 10^ (-3)

    So it follows that Molarity of ammonia = number of moles of ammonia / volume

    Molarity = 14.88 * 10^ (-3) / 5 * 10^ (-3) = 2.976 * 10^ (-3 - (-3))

    Molarity = 2.976
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