What will be the pressure of a sample of 48.0 grams of oxygen gas in a glass container of volume 5.2 l at 25 °c?

We can use the ideal gas equation based on the assumption that O₂ behaves similar to an ideal gas.

PV = nRT

P-pressure, V - volume, n - number of moles, R - universal gas constant and T - temperature

number of O₂ moles - 48.0 g / 32 g/mol = 1.5 mol

temperature - 25 °C + 273 = 298 K

substituting the values

P x 5.2 x 10⁻³ m³ = 1.5 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K

P = 714.7 kPa