How many atoms of phosphorus are in 4.50 mol of copper (ii) phosphate?

Because copper (II) cations have a charge of + 2 and phosphate anions have a charge of - 3, the formula of anhydrous * copper (II) phosphate is

Cu3 (PO4) 2

This shows that each formula unit contains 2 atoms of phosphorus. Therefore, the atoms of phosphorus in 4.8 formula units is

4.8 x Avogadro's Number (6.022x10*23), or about 2.9 X 10*24 atoms