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7 October, 13:45

What mass of znco3 contains 6.11*1022 o atoms? give your answer correctly to three significant digits?

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  1. 7 October, 14:33
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    Using Avogadros number, we can get that 1 mole of an atom contain 6.022 x 10^23 atoms. Therefore we can use this conversion factor to get the number of moles:

    moles ZnCO3 = 6.11 x 10^22 atoms * (1 mole / 6.022 x 10^23 atoms) = 0.10146 moles

    The molar mass of ZnCO3 is about 125.39 g/mol, therefore the mass is:

    mass ZnCO3 = 0.10146 moles * (125.39 g / mol)

    mass ZnCO3 = 12.72 g
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