What mass of znco3 contains 6.11*1022 o atoms? give your answer correctly to three significant digits?

Using Avogadros number, we can get that 1 mole of an atom contain 6.022 x 10^23 atoms. Therefore we can use this conversion factor to get the number of moles:

moles ZnCO3 = 6.11 x 10^22 atoms * (1 mole / 6.022 x 10^23 atoms) = 0.10146 moles

The molar mass of ZnCO3 is about 125.39 g/mol, therefore the mass is:

mass ZnCO3 = 0.10146 moles * (125.39 g / mol)

mass ZnCO3 = 12.72 g