How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?

Question

Chemistry

Paloma

30 October, 12:29

How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?

+5

Answers (1)

Know the Answer?

Jimmy Le · Answer 1

The solution for the question above is:

C = 0.270

V = 0.0275L

n = ?

Use the molar formula which is: C = n/V

Re-arrange it to: n = CV

n = (0.270) * (0.0275)

n = 0.007425 mols

(more precise) n = 7.425 x 10^-3 mols

7.425 x 10^-3 mols is the answer.