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30 October, 12:29

How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?

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  1. 30 October, 13:57
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    The solution for the question above is:

    C = 0.270

    V = 0.0275L

    n = ?

    Use the molar formula which is: C = n/V

    Re-arrange it to: n = CV

    n = (0.270) * (0.0275)

    n = 0.007425 mols

    (more precise) n = 7.425 x 10^-3 mols

    7.425 x 10^-3 mols is the answer.
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