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11 March, 21:28

Element X has two natural isotopes. The isotope with a mass of 10.012 amu has a relative abundance of 19.91%. The isotope with a mass of 11.009 amu has a relative abundance of 80.09%. Calculate the atomic mass of this element

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  1. 11 March, 22:17
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    To find the atomic mass, multiply the individual atomic masses with their relative abundances and add them up.

    10.012*0.1991 + 11.009*0.8009 = 10.810 amu (5 s. f.)

    Element X is Boron.
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