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20 August, 17:09

The voltaic cell made up of cobalt, copper, and their m2 + ions, has e°cell = 0.62 v. if e° of the cathode half-cell is 0.34 v, what is e° of the anode half-cell? cu2 + (aq) + co (s) → cu (s) + co2 + (aq)

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  1. 20 August, 20:12
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    Since that E°cell = E°cathode - E°anode then

    0.62V = 0.34 - E°anode

    Therefore E° anode is = - 0.28V
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