A 2.741 g sample of a new organic material is combusted in a bomb calorimeter. the temperature of the calorimeter and its contents increase from 24.33 °c to 28.60 °c. the heat capacity (calorimeter constant) of the calorimeter is 25.57 kj/°c, what is the heat of combustion per gram of the material?

Question

Chemistry

Shannon

4 March, 11:30

A 2.741 g sample of a new organic material is combusted in a bomb calorimeter. the temperature of the calorimeter and its contents increase from 24.33 °c to 28.60 °c. the heat capacity (calorimeter constant) of the calorimeter is 25.57 kj/°c, what is the heat of combustion per gram of the material?

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Stanley Hatfield · Answer 1

(the heat bomb calorimeter gained) = (the heat material A gave)

r. h. s=25.57 kJ/⁰C * (26.80-24.33) = 63.16 kJ

2.741g of material A made 63.16kJ

the heat of combustion per gram = 63.16/2.741 kJ/g = 24.04kJ/g