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29 February, 20:14

If 1495 J of heat is needed to raise the temperature of a 319 g sample of a metal from 55.0°C to 66.0°C, what is the specific heat capacity of the metal?

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  1. 29 February, 23:23
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    The specific heat capacity of the metal is calculated using the following formula

    Q (heat) = MC delta T

    Q = 1495 j

    c = specific heat capacity = ?

    M (mass) = 319 g

    delta T = change in temperature = 66-55 = 11 c

    by making c the subject of the formula

    C=Q / M delta T

    c = 1495 j / 319 g x 11 c = 0.426 j/g/c
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