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21 December, 17:01

When solid ammonium chloride dissociates at a certain temperature in a 0.500 dm3 container,

ammonia and hydrogen chloride are formed.

NH4Cl (s) NH3 (g) + HCl (g)

The initial amount of ammonium chloride was 1.00 mol, and when the system had reached

equilibrium there was 0.300 mol of ammonium chloride.

What is the numerical value of Kc for this reaction under these conditions?

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Answers (1)
  1. 21 December, 17:37
    0
    1) 0.500 dm3 = 0.5 liter

    2) Equilibrium reaction

    NH4Cl (s) ⇄ NH3 (g) + HCl (g)

    3) Table of changes

    Number of moles

    Species NH4Cl NH3 HCl

    Start 1mol 0 0

    Change - 0.7 + 0.7 + 0.7

    Equilibrium 0.3 0.7 0.7

    4) Equilibrium constant

    Kc = [NH3] [HCl]

    [NH3] = 0.7 mol / 0.5 liter = 1.4 M

    [HCl] = 0.7 mol / 0.5 liter = 1.4 M

    Kc = (1.4M) ^2 = 1.96M^2

    The numerical value is just 1.96 (without the units)
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