Compound j is optically active and has the molecular formula c6h10 and has a four carbon ring. on catalytic hydrogenation, j is converted to k (c6h12) and k is optically inactive. propose structures for j and k. (draw a three-dimensional formula for each using dashes and wedges around chiral centers.) j (draw one of the enantiomers) :

Question

Chemistry

Angelique Melton

9 June, 00:08

Compound j is optically active and has the molecular formula c6h10 and has a four carbon ring. on catalytic hydrogenation, j is converted to k (c6h12) and k is optically inactive. propose structures for j and k. (draw a three-dimensional formula for each using dashes and wedges around chiral centers.) j (draw one of the enantiomers) :

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Carson Orozco · Answer 1

The two possible enantiomers for the starting material and the products are shown below,

Where;

J = (S) - 1,4-dimethylcyclobut-1-ene

Or,

J = (R) - 1,4-dimethylcyclobut-1-ene

And,

K = 1,2-dimethylcyclobutane

Both enantiomers have same molecular formula (C₆H₁₀) but different stereochemistry about chiral carbon.

Upon catalytic hydrogenation two hydrogen atoms are added across double bond resulting in the formation of cyclobutane.