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Chemistry
Kolton Shah
9 January, 00:30
A solution has a pH of 2.5. What is its [OH-]?
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Bernard Chaney
9 January, 04:15
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POH=14-pH=14-2.5=11.5 pH=-log[H+] 2.5=-log [H+] [H+]=10^-5/2 [OH-]=10^ (14-5/2) = 10^23/2
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