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27 July, 09:21

An automobile tire is inflated to a pressure of 3.05 atm on a rather warm day when the temperature is 40 C. The car is then driven to the mountains and parked overnight. The morning temperature is - 5.0 C (five below zero). What will the pressure of the gas be in the tire at this temperature? Assume the volume of the tire doesn't change.

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  1. 27 July, 12:54
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    P1 = 3.05atm, T1 = 40C, T2 = - 5.0C

    T1 = 273+40 = 313K, T2=273K-5.0C = 268K

    Use P1V1/T1 = P2V2/T2, but V1=V2 so they cancel each other out:

    P1/T1 = P2/T2 - - > P2 = P1T2/T1

    P2 = (3.05) (268) / 313 = 2.61 atm
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