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7 August, 08:27

If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced?

2 KClO3 → 2 KCl + 3 O2

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  1. 7 August, 10:38
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    Moles of KClO₃ = 59.3 / (39 + 35.5 + 16 x 3)

    Moles of KClO₃ = 0.48

    Molar ratio of KClO₃ to O₂ = 2 : 3

    Moles of O₂ produced = 1.5 x 0.48

    = 0.72

    Mass of O₂ = moles x Mr

    = 0.72 x 32

    = 23.04 grams
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