If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced?

2 KClO3 → 2 KCl + 3 O2

Question

Chemistry

Ignacio Wilson

7 August, 08:27

If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced?

2 KClO3 → 2 KCl + 3 O2

+5

Answers (1)

Know the Answer?

Isis Rose · Answer 1

Moles of KClO₃ = 59.3 / (39 + 35.5 + 16 x 3)

Moles of KClO₃ = 0.48

Molar ratio of KClO₃ to O₂ = 2 : 3

Moles of O₂ produced = 1.5 x 0.48

= 0.72

Mass of O₂ = moles x Mr

= 0.72 x 32

= 23.04 grams

If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced?2 KClO3 → 2 KCl + 3 O2

If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced?

2 KClO3 → 2 KCl + 3 O2