Ask Question
27 October, 20:01

A chemist heats 100.0 g of FeSO4 x 7H2O in a crucible to drive off the water. If all the water is driven off, what is the mass of the remaining salt?

+3
Answers (1)
  1. 27 October, 22:55
    0
    FeSO₄*7H₂O (s) = FeSO₄ (s) + 7H₂O (g)

    M (FeSO₄*7H₂O) = 278.0 g/mol

    M (FeSO₄) = 151.9 g/mol

    m (FeSO₄*7H₂O) / M (FeSO₄*7H₂O) = m (FeSO₄) / M (FeSO₄)

    m (FeSO₄) = M (FeSO₄) m (FeSO₄*7H₂O) / M (FeSO₄*7H₂O)

    m (FeSO₄) = 151.9*100.0/278.0=54.6 g

    m (FeSO₄) = 54.6 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A chemist heats 100.0 g of FeSO4 x 7H2O in a crucible to drive off the water. If all the water is driven off, what is the mass of the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers