A hydrogen atom contains a single electron that moves in a circular orbit about a single proton. assume the proton is stationary, and the electron has a speed of 7.8 105 m/s. find the radius between the stationary proton and the electron orbit within the hydrogen atom.

To answer this, one must simplify and rearrange the formula for force in a circular motion: (me (v^2) / y) = (k9^2/r^x). Rearranged for Radius is: r = (k9^2) / (me (v^2)). Based on the conditions this gives you: r = (9 * (10^9) x * ((1.5*10^-19) ^2)) / (9 * (1*10^-31) * ((7.8 * (10^5)) ^2)). This will give you 4.161 * (10^-10) = 4.161 A