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14 March, 05:39

Describe how you would prepare 350 ml of 0.100 m c12h22o11 starting with 3.00l of 1.50 m c12h22o11

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  1. 14 March, 07:31
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    To prepare 350 mL of 0.100 M solution from a 1.50 M solution, we simply have to use the formula:

    M1 V1 = M2 V2

    So from the formula, we will know how much volume of the 1.50 M we actually need.

    1.50 M * V1 = 0.100 M * 350 mL

    V1 = 23.33 mL

    So we need 23.33 mL of the 1.50 M solution. We dilute it with water to a volume of 350 mL. So water needed is:

    350 mL - 23.33 mL = 326.67 mL water

    Steps:

    1. Take 23.33 mL of 1.50 M solution

    2. Add 326.67 mL of water to make 350 mL of 0.100 M solution
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