For the reaction a2 + b2 → 2ab, ea (fwd) = 105 kj/mol and ea (rev) = 77 kj/mol. assuming the reaction occurs in one step, calculate δh°rxn

Question

Chemistry

Payton Douglas

15 February, 23:19

For the reaction a2 + b2 → 2ab, ea (fwd) = 105 kj/mol and ea (rev) = 77 kj/mol. assuming the reaction occurs in one step, calculate δh°rxn

+3

Answers (1)

Know the Answer?

Trevon Mora · Answer 1

Answer is: 28 kJ.

Chemical reaction: A₂ + B₂ ⇄ 2AB.

Ea (forward) = 105 kJ/mol.

Ea (reverse) = 77 kJ/mol.

ΔH (reaction) = ?

The enthalpy change of reaction is the change in the energy of the reactants to the products.

ΔH (reaction) = Ea (forward) - Ea (reverse).

ΔH (reaction) = 105 kJ/mol - 77 kJ/mol.

ΔH (reaction) = 28 kJ/mol; this is endothermic reaction (ΔH > 0).