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26 January, 20:48

Use the problem below to answer the question.

HCl + NaOH → NaCl + H2O

1. If 30g of HCl is reacted with excess NaOH, and 10g of NaCl is produced, what is the theoretical yield of the experiment?

2. If 30 g of HCl is reacted with excess NaOH, and 10 g of NaCl is produced, what is the percent yield of the experiment?

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  1. 26 January, 22:46
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    1. 10 g HCl x 1 mol Hcl/36g HCl (molar mass) x 1mol H2O / 1mol HCl = 0.27mol H2O (Limiting Reactant)

    0.27 mol H2O x 18 g H2O / 1 mol H2O = 4.86 g H2O (Theoretical yield)

    2. %yield = actual yield / theoretical yield x 100

    = 3 g / 4. 46 g x 100

    = 62.11 % percent yield
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