Ask Question
11 December, 15:42

If 41grams of water at 24°C absorbs 2208 J of heat energy, what will be the final temperature of the water?

+2
Answers (1)
  1. 11 December, 17:48
    0
    The problem can solved using the heat equation which is expressed as:

    H = mCΔT

    where H is the energy absorbed or released, m is the mass of the substance, C is the specific heat capacity, and ΔT is the change in temperature.

    2208 J = 41 g x 4.18 J/g·°C x (T - 24 °C)

    T = 36.88 °C
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If 41grams of water at 24°C absorbs 2208 J of heat energy, what will be the final temperature of the water? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers