What is the pressure exerted by 1.2 mol of a gas with a temperature of 20.°c and a volume of 9.5 l?

Let's assume that the gas is an ideal gas. Then we can use ideal gas equation,

PV = nRT

Where,

P = Pressure of the gas (Pa)

V = volume of the gas (m³)

n = number of moles (mol)

R = Universal gas constant (8.314 J mol ⁻¹ K⁻¹)

T = temperature in Kelvin (K)

The given data for the gas is,

P = ?

V = 9.5 L = 9.5 x 10 ⁻³ m³

T = (273 + 20) K = 293 K

R = 8.314 J mol ⁻¹ K⁻¹

n = 1.2 mol

by applying the formula,

P x 9.5 x 10⁻³ m³ = 1.2 mol x 8.314 J mol⁻¹ K⁻¹ x 293 K

P = 307705.5 Pa

P = 3.08 x 10 ⁵ Pa

Hence, the pressure of the gas is 3.08 x 10⁵ Pa.