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2 January, 16:48

A hypothetical pure element consists entirely of two isotopes. the natural percent abundance of the isotope with mass 25.2 u is 80.1%. the other isotope has mass 29.4 u. calculate the atomic weight of the naturally occurring element

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  1. 2 January, 18:34
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    The atomic weight of the naturally occurring element would simply be the weighted average of the two isotopes. Calculating:

    atomic weight = (25.2 g / mol) * 0.801 + (29.4 g / mol) * (1 - 0.801)

    atomic weight = 26.04 g / mol
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