If 22.50 mL of a sodium hydroxide solution is necessary to neutralize 18.50 mL of a 0.1430 M HNO3 solution, what is the concentration of the NaOH? (Report your answer in molarity.)

Question

Chemistry

Deacon

28 September, 16:23

If 22.50 mL of a sodium hydroxide solution is necessary to neutralize 18.50 mL of a 0.1430 M HNO3 solution, what is the concentration of the NaOH? (Report your answer in molarity.)

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Darryl Mcdaniel · Answer 1

The concentration of NaOH is calculated as follows

calculate the moles of HNO3

moles = molarity x volume

=18.50 x0.1430 = 2.6455 moles

write the reacting equation

that is

NaOH + HNO3 = NaNO3 + H2O

by use mole ratio between NaOH: HNO3 the moles of NaOH is also 2.6455moles

concentration is therefore moles/volume

= 2.6455 / 22.50 = 0.118M