Ask Question
28 October, 04:55

A chemist requires 0.446 mol na2co3 for a reaction. how many grams does this correspond to?

+2
Answers (1)
  1. 28 October, 06:55
    0
    The amount of moles of Na₂CO₃ required = 0.446 moles

    to find out the mass of Na₂CO₃ required, we need to find out its molar mass.

    Molar mass is the mass of one mole of the element / compound.

    molar masses of the elements are as follows;

    Na - 23 g/mol

    C - 12 g/mol

    O - 16 g/mol

    Molar mass of Na₂CO₃ can be calculated as follows;

    (Na * 2) + C + (O * 3)

    (23*2) + 12 + (16*3)

    = 46 + 12 + 48

    =106 g/mol

    1 mol of Na₂CO₃ weighs - 106 g

    Therefore 0.446 mol = 106 g/mol * 0.446 mol = 47.27g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A chemist requires 0.446 mol na2co3 for a reaction. how many grams does this correspond to? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers