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7 February, 13:59

What is the molar mass of a solution of 5.00 g of a compound in 25.00 g of carbon tetrachloride (bp 76.8 °c; kb = 5.02 °c/m) that boils at 81.5 °c at 1 atm? (a) outline the steps necessary to answer the question?

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  1. 7 February, 14:16
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    (84.4C - 76.5C) / (5.03 C/m) = 1.5706 m

    (1.5706 mol) / (1000 g CC14) X (25.00 G CC14) = 0.039265 mol

    (5.00 g) / (0.039265 mol) = 127 g/mol
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