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17 February, 14:30

Calculate the grams of sodium hydroxide formed when 2.24 moles of sodium oxide react with water

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  1. 17 February, 16:57
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    The balanced reaction is

    Na2O + H2O - - > 2NaOH

    If 2.24 moles of sodium oxide react, that means 4.48 moles of NaOH is formed as it is a 1 to 2 stoichiometric relationship.

    Now we multiply by the molar mass to get grams.

    4.48 moles NaOH * (39.997 grams/1 mole) = 179.2 grams

    Your answer is 179. grams.
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