Calculate the grams of sodium hydroxide formed when 2.24 moles of sodium oxide react with water

The balanced reaction is

Na2O + H2O - - > 2NaOH

If 2.24 moles of sodium oxide react, that means 4.48 moles of NaOH is formed as it is a 1 to 2 stoichiometric relationship.

Now we multiply by the molar mass to get grams.

4.48 moles NaOH * (39.997 grams/1 mole) = 179.2 grams

Your answer is 179. grams.