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4 October, 01:33

How would you classify a solution if [OH-] = 4.2 x 10-8 M?

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  1. 4 October, 05:31
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    Answer: Slightly acid, almost neutral.

    pOH = - log [OH - ] = - log [4.2 x 10^-8] = 7.38

    pH + pOH = 14 = = > pH = 14 - pOH = 14 - 7.38 = 6.62.

    Remember: 7 is neutral, below 7 is acid. This solution is almost neutral.
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