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13 July, 21:50

Calculate the molar solubility and the solubility in g / l of agi at 25°c. the ksp of agi is 8.3 * 10-17.

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  1. 13 July, 23:22
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    Answer is: solubility of silver iodide is 9.11·10⁻⁹ M ...

    silver iodide in water: AgI (s) → Ag⁺ + I⁻.

    Ksp = 8.3 ·10⁻¹⁷.

    [Ag ⁺] = [I⁻] = x.

    Ksp = [Ag ⁺] · [I⁻].

    8.3·10⁻¹⁷ = x².

    x = √ 8.3·10⁻¹⁷.

    x = [Ag ⁺] = [I⁻] = 9.11·10⁻⁹ mol/L.
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