Ask Question
7 July, 10:12

It takes 11.2 kj of energy to raise the temperature of 145 g of benzene from 22.0°c to 67.0°c. what is the specific heat of benzene? it takes 11.2 kj of energy to raise the temperature of 145 g of benzene from 22.0°c to 67.0°c. what is the specific heat of benzene? 5.18 j / (g * °c) 3.48 j / (g * °c) 1.15 j / (g * °c) 1.72 j / (g * °c)

+3
Answers (1)
  1. 7 July, 13:44
    0
    We can use the heat equation,

    Q = mcΔT

    where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

    Q = 11.2 kJ = 11200 J

    m = 145 g

    c = ?

    ΔT = (67 - 22) °C = 45 °C

    By applying the formula,

    11200 J = 145 g x c x 45 °C

    c = 1.72 J g⁻¹ °C⁻¹

    Hence, specific heat of benzene is 1.72 J g⁻¹ °C⁻¹.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “It takes 11.2 kj of energy to raise the temperature of 145 g of benzene from 22.0°c to 67.0°c. what is the specific heat of benzene? it ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers