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3 September, 17:43

Calculate the number of chlorine atoms that are present in 66.05 g of dichloromethane, ch2cl2. when you have the number, take its log (base 10) and enter it with three decimal places and without units.

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  1. 3 September, 19:20
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    From the periodic table:

    mass of carbon = 12 grams

    mass of hydrogen = 1 gram

    mass of chlorine = 35.5 grams

    Therefore,

    molar mass of CH2Cl2 = 12 + 2 (1) + 2 (35.5) = 85 grams

    number of moles = mass / molar mass

    number of moles of CH2Cl2 = 66.05 / 85 = 0.777 moles

    One mole of CH2Cl2 contains two moles of Cl and each chlorine mole has Avogadro's number of atoms in it.

    Therefore,

    number of chlorine atoms in 0.777 moles of CH2Cl2 can be calculated as follows:

    number of atoms = 0.777 * 2 * 6.022 * 10^23 = 9.358 * 10^23 atoms

    Now, we will take log base 10 for this number:

    log (9.358 * 10^23) = 23.97119
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