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14 July, 05:48

If a balloon is expanded from 0.055 l to 1.403 l against an external pressure of 1.02 atm, how many l⋅atm of work is done?

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  1. 14 July, 05:56
    0
    Work for a irreversible reaction, in thermodynamics, is calculated by multiplying the external pressure with the change in volume. Therefore,

    Work = P (V2 - V1)

    Work = 1.02 (1.403 - 0.055)

    Work = 1.375 L-atm

    Hope this answers the question. Have a nice day.
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