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21 September, 06:43

How many liters of 0.1107 M KCI contains 15.00 g of KCI (FW = 74.6 g/mol)

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  1. 21 September, 08:44
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    Number of moles:

    n = sample mass / molar mass

    n = 15.00 / 74.6

    n = 0.2010 moles of KCl

    Therefore:

    Molarity = moles / Volume

    0.1107 = 0.2010 / V

    V = 0.2010 / 0.1107

    V = 1.815 L
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