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5 April, 10:24

What is the true, molecular formula of a compound with the empirical formula C13H19O2 and molar mass of 414.64g?

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  1. 5 April, 12:50
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    C13H19O2 = (12 * 13) + (1 * 19) + (16 * 2) = 156 + 19 + 32 = 207.

    The formula is n = molar mass of molecular formular / molar mass of empirical formular. MM of molecular formula = 414.7 and of empirical formula = 207

    So n = 414.7 / 207 = 2.

    So the true molecular formula is 2 (C13H19O9) = C26H38O18.
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