Find the pressure in mm Hg produced by 2.35g of carbon dioxide in a 5.00L flask at 18 degrees Celsius.

Moles of CO₂ = 2.35/44 = 0.0534 mole.

From ideal gas equation PV=nRT,

T = 18+273K = 291 Kelvin.

∴Px5 = 0.0534x0.0821x291

∴P = 0.0534x0.0821x291/5 = 0.2551 atm.

Now, 1 atm = 760 mm of Hg

∴ 0.02551 atm = 0.02551 x 760 = 19.38 mm of Hg